??? 07/19/06 20:39 Read: times |
#120630 - BC556 base current direction... Responding to: ???'s previous message |
Kai Klaas said:
This current divides then into 0.7V/10kOhm = 70µA flowing through the upper 10k resistor and the rest of 430µA - 70µA = 360µA flowing through the base emitter junction.
isn't the direction of base current towards the port pin? thats why i did 430uA + 70uA, which is obviously going to be the sink current. Thanking you, Suresh. |