??? 07/19/06 18:41 Read: times |
#120623 - Thank you very much! Responding to: ???'s previous message |
Kai,
Thanks for such a detailed explanation. It gave me many information. also, for the analysis for BC 556 part, I tried as such., once the port changes to logic low state, the current flowing through the 10K resistors is = 70uA (.7 V drop in each 10K resistor) At this instant, the transistor is about to turn ON. Once turned ON, the current through the 10K (in base) = (4.3/10000)+ 70uA = .5mA So only at .5mA of base current of BC 556, its collector current becomes 3.58mA. Is this correct? Suresh. |