??? 08/22/07 06:05 Read: times |
#143496 - >Dissipation constant< gives the answer Responding to: ???'s previous message |
What i understand
"dissipation constant" of 1mW/°C For 100 µW/0.1°C So maximum this much power (100 µW) dissipation is valid for thermistor to not degrade the performance. The thermistor resistor at 37 °C= 6.2 Kohm If I take 6.2 k( Precise resistor as suggest by Kai) then the current is (5/(6.2+6.2)Kohm)=4.0322E-4 Amp and so power dissipation in thermistor is (((4.0322E-4)^2)*6.2Kohm)=1.008E-3 watt Approximately 1 mw power dissipated in the thermistor. Is it tolerable. |
Topic | Author | Date |
Thermistor Self-heating | 01/01/70 00:00 | |
Error budget | 01/01/70 00:00 | |
Use a bridge configuration | 01/01/70 00:00 | |
Error Budget | 01/01/70 00:00 | |
measurement point | 01/01/70 00:00 | |
measurement point | 01/01/70 00:00 | |
Math | 01/01/70 00:00 | |
>Dissipation constant< gives the answer | 01/01/70 00:00 | |
Amplify | 01/01/70 00:00 | |
The Center is not the only factor | 01/01/70 00:00 | |
Linearisation | 01/01/70 00:00 | |
>Dissipation constant< gives the answer | 01/01/70 00:00 | |
Getting closer | 01/01/70 00:00 | |
Correcting non Linearisation of thermister | 01/01/70 00:00 | |
1721 | 01/01/70 00:00 | |
Nice link | 01/01/70 00:00 | |
Measuring thermistors | 01/01/70 00:00 | |
Braggard? Show your work | 01/01/70 00:00 | |
nope | 01/01/70 00:00 | |
ADC selection. | 01/01/70 00:00 | |
Depends on your application | 01/01/70 00:00 | |
The Components | 01/01/70 00:00 | |
Accuracy... | 01/01/70 00:00 | |
What BETA? 3890K or 3575K? | 01/01/70 00:00 | |
This thread might be helpful for you![]() | 01/01/70 00:00 |