??? 12/19/08 23:21 Modified: 12/20/08 00:01 Read: times Msg Score: 0 -1 Didn't Search First +1 Underrated |
#161065 - instruction cycle |
What will be the time for '1 instruction cycle' or a 'nop' to the ADUC841 using a crystal 11.059Mhz with 2^0(CD) ?
Am I correct with a formula below ? 'nop' = 1/((11.059E6/12)/2^0) Calix |
Topic | Author | Date |
instruction cycle | 01/01/70 00:00 | |
bible time? | 01/01/70 00:00 | |
Read doc's | 01/01/70 00:00 | |
He did | 01/01/70 00:00 | |
Apologies | 01/01/70 00:00 | |
bible can be incorrect | 01/01/70 00:00 | |
"the bible" is gospel | 01/01/70 00:00 | |
That was specifically noted | 01/01/70 00:00 | |
understood | 01/01/70 00:00 | |
ADuC841 is a single-clocker![]() | 01/01/70 00:00 |