??? 04/10/06 17:03 Read: times |
#114007 - Typo Responding to: ???'s previous message |
It works simply so that it emits the value from Ri to low address bus, while the high address bus (=P2) remains unaltered (=P2). not fully wrong its just a typo. Abhishek |
Topic | Author | Date |
unclarity with movx instruction | 01/01/70 00:00 | |
Speed up | 01/01/70 00:00 | |
Mistake | 01/01/70 00:00 | |
Clarity prevails! | 01/01/70 00:00 | |
Quicker? | 01/01/70 00:00 | |
Quicker! | 01/01/70 00:00 | |
assumption... | 01/01/70 00:00 | |
Finally, you are right! | 01/01/70 00:00 | |
MOVX @Ri | 01/01/70 00:00 | |
since you did not have the time to find | 01/01/70 00:00 | |
wrong answer | 01/01/70 00:00 | |
Typo | 01/01/70 00:00 | |
thanks Erik for the correction | 01/01/70 00:00 | |
It is set to P0 | 01/01/70 00:00 | |
wrong again | 01/01/70 00:00 | |
Yes I am | 01/01/70 00:00 | |
an example | 01/01/70 00:00 | |
Internal XRAM | 01/01/70 00:00 | |
not really | 01/01/70 00:00 | |
Ports' SFR are set to 1 | 01/01/70 00:00 | |
not a port, a "page SFR"![]() | 01/01/70 00:00 | |
P2? | 01/01/70 00:00 | |
Doh! | 01/01/70 00:00 | |
which derivative | 01/01/70 00:00 | |
do not allow? | 01/01/70 00:00 | |
AT89S8252 | 01/01/70 00:00 | |
Aaaaah, so. Thanks. | 01/01/70 00:00 | |
Tanks | 01/01/70 00:00 |