| ??? 03/02/06 00:49 Read: times |
#111020 - OK Responding to: ???'s previous message |
You have looked at the problem and made an informed decsion.
You have a solution. If you mean M0 = 0 and M1 = 1 then TH1 holds the reset value TL0 is the counter. TL0 can be left as is or set to zero. |
| Topic | Author | Date |
| putchar C51 serial communication problem | 01/01/70 00:00 | |
| Keil putchar source | 01/01/70 00:00 | |
| putchar() reworded | 01/01/70 00:00 | |
| TI | 01/01/70 00:00 | |
| thanks and here is my C code of asm... | 01/01/70 00:00 | |
| should be obvious | 01/01/70 00:00 | |
| To be fair | 01/01/70 00:00 | |
| C gives higher performance! | 01/01/70 00:00 | |
| Initial conditions | 01/01/70 00:00 | |
| waiting better than uninten effcy | 01/01/70 00:00 | |
| Better? | 01/01/70 00:00 | |
| Math? | 01/01/70 00:00 | |
| What????? | 01/01/70 00:00 | |
| no work to do unitl bytes send | 01/01/70 00:00 | |
| OK | 01/01/70 00:00 | |
| or... | 01/01/70 00:00 | |
| That is better | 01/01/70 00:00 | |
| i read about putchar() | 01/01/70 00:00 | |
| Try \Keil\C51\LIB\getkey.c | 01/01/70 00:00 | |
| Keil Library Source Files | 01/01/70 00:00 | |
| ok | 01/01/70 00:00 | |
| No and Yes | 01/01/70 00:00 | |
| but what about AT cmd | 01/01/70 00:00 | |
No | 01/01/70 00:00 |