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Dear Santosh,

your stpper seems to be a Unipolar motor which can be seen as

winding 1                winding 2
-----@@@@@@@-------    -----@@@@@@@-------
        |                      |
        |                      |
      center tap            center tap

here is teh equalant circuit of an stepper winding

winding resistance  winding inductance

-----/\/\/\/\/\-----@@@@@@@---------

you have said that 0.16 A /phase. i suggest you go with following procedure.

take any one lead common and measure the resistance with others.
you will notice that three leads are open with respect to common lead. exclude them from your test. they belong to other winding.
rest of the two will show either

1. equal resistance with respect to the common lead, in this case your common lead is the center tap for the rest of the two.

2. one lead show double resistance than the other with respect to the common lead.In this case the lead which shows minimum resistance is the center tap.

repeat step 1 and 2 with excluded leads and find the center tap.



now if resistance of each winding is R then find the voltage by V = 0.16*R/2.

right sequence for wave drive can be determined by trial and error(not many perm/comb).

if you want to run these stepper at high torqe and speed you need a chopper stepper driver like L297 + L298 pair otherwise even wave drive can suffice.


Abhishek