| ??? 01/03/06 03:16 Read: times |
#106396 - back to basics (too long ago) Responding to: ???'s previous message |
The two caps appear to be in series for the crystal. So, the capacitive load is (burden cap + XTAL port stray capacitance) / 2. Two identical caps in series give a capacitance of half the single capacitance. I'm pretty sure I get this part. Electronics is my first love, but it's been 25 years since I spent any time using it. I went to SW instead (I hate trig and calc) Kevin, don't stop asking! The more the better! It's a plain pleasure to discuss with someone how is such eager to learn like you. Keep the shining in your eyes... Be careful what you ask for, you might get it :) |
| Topic | Author | Date |
| Crystal Load Capacitance (redux) | 01/01/70 00:00 | |
| Load capacitance | 01/01/70 00:00 | |
| much thanks | 01/01/70 00:00 | |
| Burden caps appear to be in series | 01/01/70 00:00 | |
| back to basics (too long ago) | 01/01/70 00:00 | |
| crystals available | 01/01/70 00:00 | |
Doesn't really matters | 01/01/70 00:00 |