| ??? 01/03/06 02:11 Read: times |
#106395 - Burden caps appear to be in series Responding to: ???'s previous message |
Kevin said:
Finally, it seems your computation is based upon just one 18pf cap + 5pf (23pf) / 2 = 11.5 (12pf) Is that correct? The two caps appear to be in series for the crystal. So, the capacitive load is (burden cap + XTAL port stray capacitance) / 2. Two identical caps in series give a capacitance of half the single capacitance. Kevin said:
I'll ask a million questions for a week, but hardly even one question after that. Once I get the first loader and then the first circuit built, the silence will be deafening! Kevin, don't stop asking! The more the better! It's a plain pleasure to discuss with someone how is such eager to learn like you. Keep the shining in your eyes... Kai |
| Topic | Author | Date |
| Crystal Load Capacitance (redux) | 01/01/70 00:00 | |
| Load capacitance | 01/01/70 00:00 | |
| much thanks | 01/01/70 00:00 | |
| Burden caps appear to be in series | 01/01/70 00:00 | |
| back to basics (too long ago) | 01/01/70 00:00 | |
| crystals available | 01/01/70 00:00 | |
Doesn't really matters | 01/01/70 00:00 |