| ??? 05/25/05 17:24 Read: times |
#93898 - Looks the same to me Responding to: ???'s previous message |
Donald Catto said:
"Neil's point is that, although pointers & arrays are different, they both use the same Notation."
No. He states that "pointer notation and array notation are interchangeable". He does not state that "[pointers and arrays] use the same notation", which is even less correct, if it is possible to have a state of 'less correct'. By "Notation," I'm thinking of: void main( void )
{
char my_array[] = "Array";
char *my_pointer = "Pointer";
char my_char;
my_char = my_array[0];
my_char = my_pointer[0];
my_char = *my_array;
my_char = *my_pointer;
}
The differences lie in the behaviour: |
| Topic | Author | Date |
| Unions in C | 01/01/70 00:00 | |
| You miss the point completely... | 01/01/70 00:00 | |
| Easy with Union | 01/01/70 00:00 | |
| You can see from the Raghu example... | 01/01/70 00:00 | |
| Platform-dependence | 01/01/70 00:00 | |
| Padding in unions | 01/01/70 00:00 | |
| portability | 01/01/70 00:00 | |
| array=pointer...? | 01/01/70 00:00 | |
| array != pointer | 01/01/70 00:00 | |
| Quirk of C | 01/01/70 00:00 | |
| Read the FAQ | 01/01/70 00:00 | |
| Read the Comment | 01/01/70 00:00 | |
| Read everything | 01/01/70 00:00 | |
| Looks the same to me | 01/01/70 00:00 | |
| This One | 01/01/70 00:00 | |
| That's the problem | 01/01/70 00:00 | |
| Good example | 01/01/70 00:00 | |
| No fun | 01/01/70 00:00 | |
| Well... | 01/01/70 00:00 | |
| Of course it does! | 01/01/70 00:00 | |
| Hmm | 01/01/70 00:00 | |
| Actually, even less. | 01/01/70 00:00 | |
| const pointer | 01/01/70 00:00 | |
| O.K you win | 01/01/70 00:00 | |
| Please conclude | 01/01/70 00:00 | |
| Not Exactly | 01/01/70 00:00 | |
End of wrong stick? | 01/01/70 00:00 |



