| ??? 01/06/06 13:51 Read: times |
#106701 - the only 16 bit register in th1 '51 is t Responding to: ???'s previous message |
Now i splitted my 8 bit number into two 4 bit numbers.
But does this work with 16 bit to 8 bit. Of course i tried this Method but Keil always warns be because of truncating value to 8 bits !! The only 16 bit register in the '51 is the DPTR so anything else MUST be truncated to 8 bits. Ok so, as an example, you want a variable such as 0x1234 to go in R0 and R1. value equ 01234h mov r0,HIGH value mob r1 LOW value will make r0 12 and r1 34 Erik |
| Topic | Author | Date |
| 16 bit to 8 bit | 01/01/70 00:00 | |
| the only 16 bit register in th1 '51 is t | 01/01/70 00:00 | |
| using relocatable segment | 01/01/70 00:00 | |
| it is not Keil, it is the processor | 01/01/70 00:00 | |
| SMS | 01/01/70 00:00 | |
| TIA | 01/01/70 00:00 | |
| Hope This Helps | 01/01/70 00:00 | |
| RTFM (please read) | 01/01/70 00:00 | |
| That may be what you mean but | 01/01/70 00:00 | |
| well, I did not | 01/01/70 00:00 | |
| Didn't know | 01/01/70 00:00 | |
| that I do | 01/01/70 00:00 | |
| Just goes to prove my point | 01/01/70 00:00 | |
| Is that an excuse for not trying to make | 01/01/70 00:00 | |
| Its a hint | 01/01/70 00:00 | |
Hope That Helps | 01/01/70 00:00 |