| ??? 06/22/05 12:31 Read: times |
#95578 - based on the above Responding to: ???'s previous message |
is it possible to solving this problem with a software method
the answer may be yes if you have while (pin); instead of for (timeout = nnn; timeout !=0; timeout--)
{
if (pin)
{
break;
}
}
if (!pin)
{
error();
}
you are, indeed asking for punishment. Erik |



