| ??? 04/25/05 02:07 Read: times |
#92282 - Answered Responding to: ???'s previous message |
Hi William,
Peter had posted the answers to #14 and #15. Not sure why you posted the questions again.. "mov dptr, #$" is a statement which most assemblers will understand as move the current contents of PC to dptr. Similiar to "jmp $" which will result in a jump to the same address as is current. As to the answer for #15, it is straight forward. Raghu |
| Topic | Author | Date |
| MOV PC.DPTR | 01/01/70 00:00 | |
| I haven't got the book | 01/01/70 00:00 | |
| Kenneth Ayla ? | 01/01/70 00:00 | |
| HeHe You Are RIght... | 01/01/70 00:00 | |
| Ayala Book Page 99 Scan | 01/01/70 00:00 | |
| Re 14&15 | 01/01/70 00:00 | |
| MOV PC.DPTR | 01/01/70 00:00 | |
| Answered | 01/01/70 00:00 | |
MOV PC.DPTR | 01/01/70 00:00 |