Robert, if all you want to do is wait for 5msec you don't need to get this complicated !

Pretty good for the rest of it, Your structure is fine, your algorithm isn't....

All you need to do is set the timer and wait for the overflow flag. With a standard crystal, you don't even need to count overflows

The algorithm is

set timer to count out in 5msec.
start timer
Set timer interrupt
set EA.
set flag to say wait is in progress


Now do your program while waiting for the flag to clear.

;do something
;While wait flag is true



Your interrupt code is

CLR wait_flag
RETI

Easy

Steve