| ??? 10/19/07 08:16 Read: times |
#145941 - No, it's not correct Responding to: ???'s previous message |
Brett Wallace said:
I think you are correct, a word should be 2 bytes and a double word would be 4 bytes. No, that is not generally correct. It is correct for a 16-bit architecture, but is not correct as a general statement. See: http://www.8052.com/forum/read.phtml?id=145940 Of course, the specific term "dword" in a specifc x86 assembler probably is defined to mean 32 bits; Similarly, microsoft's specific term "DWORD" as used in the windoes API probably is defined to mean 32 bits - but you cannot just apply that definition outside that specific context! |
| Topic | Author | Date |
| ASCII to Binary in Assembly | 01/01/70 00:00 | |
| What guidance do you need? | 01/01/70 00:00 | |
| this might be part of the fun :-) | 01/01/70 00:00 | |
| Not 8051? | 01/01/70 00:00 | |
| Isn't a double 32 bits? | 01/01/70 00:00 | |
| I think so | 01/01/70 00:00 | |
| No, it's not correct | 01/01/70 00:00 | |
| No, that's wrong. | 01/01/70 00:00 | |
Thanks | 01/01/70 00:00 | |
| I'm here so far !! | 01/01/70 00:00 | |
| Definitely not 8051! | 01/01/70 00:00 | |
| you are on 8052.com... | 01/01/70 00:00 | |
| Sorry Andy | 01/01/70 00:00 | |
| Leg up | 01/01/70 00:00 | |
| I think i got it! may u check it? | 01/01/70 00:00 | |
| listen to your teacher | 01/01/70 00:00 | |
| Check | 01/01/70 00:00 | |
| Bonus question | 01/01/70 00:00 | |
| Lol | 01/01/70 00:00 |