| ??? 04/22/06 23:07 Read: times |
#114758 - BCD Responding to: ???'s previous message |
The lower nibble has a number 0 to 9, Same for the upper one.
So 1 byte holds 0 to 99. So assuming 99d (63hex) would be 153( 99h) One way divide by 10 and save the remiander Then multi by 16 and add the remainder. But you are using ASM You could SWAP nibbles to avoid the multiplication. Look at the DAA instruction if you are doing BCD math. |
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